Willer Academy
Nation Builders Through Education | Founded by Er. Rahul Kumar Dubey Sir
Chapter 6: Triangles
Subject: Mathematics
Class: 10
Series: Base Builder for Moderate to Hard
Learning Objectives
By the end of this chapter, you, the future mathematician and nation-builder, will be able to:
- Understand the properties and types of triangles
- Apply various similarity criteria to prove triangle similarity
- Use the Basic Proportionality Theorem (Thales Theorem) to solve problems
- Apply Pythagoras Theorem and its converse to solve problems
- Understand and apply area relationships in similar triangles
- Solve problems involving triangles in real-life situations
- Prove geometric theorems related to triangles
6.1 Introduction: Understanding Triangles
A triangle is a closed figure with three sides, three angles, and three vertices. It is one of the basic shapes in geometry and has numerous properties and applications.
Quick Check
Look around you and identify five objects that have triangular shapes. What purpose does the triangular shape serve in each object?
6.2 Types of Triangles
Triangles can be classified based on their sides or angles, each with unique properties.
By Sides
- Scalene: All sides different
- Isosceles: Two sides equal
- Equilateral: All sides equal
By Angles
- Acute: All angles < 90°
- Right: One angle = 90°
- Obtuse: One angle > 90°
Similar Triangles
- Same shape but different size
- Corresponding angles equal
- Corresponding sides proportional
Numerical & Application 1: Angle Sum Property
- Scenario: In a triangle, two angles measure 45° and 60°.
- Problem: What is the measure of the third angle? What type of triangle is it based on angles?
- Solution:
- Sum of angles in a triangle = 180°
- Third angle = 180° - (45° + 60°) = 75°
- All angles are less than 90°, so it's an acute triangle
This demonstrates the angle sum property of triangles!
6.3 Similarity of Triangles
Two triangles are similar if their corresponding angles are equal and corresponding sides are proportional.
| Criterion | Explanation | Symbol |
|---|---|---|
| AAA | If corresponding angles are equal | ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R |
| SSS | If corresponding sides are proportional | AB/PQ = BC/QR = AC/PR |
| SAS | If one angle equal and including sides proportional | ∠A = ∠P and AB/PQ = AC/PR |
Basic Proportionality Theorem (Thales Theorem)
If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio.
In ΔABC, if DE ∥ BC, then AD/DB = AE/EC
Task 1: Similarity Proof
In triangle ABC, points D and E are on sides AB and AC respectively such that DE ∥ BC. If AD = 3 cm, DB = 2 cm, and AE = 4.5 cm, find EC.
6.4 Pythagoras Theorem
In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Pythagoras Theorem
In a right triangle ABC, right-angled at B: AC² = AB² + BC²
Numerical & Application 2: Pythagoras Theorem
- Scenario: A ladder 5 m long is placed against a wall such that it reaches a height of 4 m.
- Problem: How far is the foot of the ladder from the wall?
- Solution:
- Let the distance be x meters
- Using Pythagoras theorem: x² + 4² = 5²
- x² + 16 = 25 → x² = 9 → x = 3 m
This shows how Pythagoras theorem applies to real-world situations!
6.5 Area of Similar Triangles
The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
Area Ratio
If ΔABC ~ ΔPQR, then
Area(ΔABC)/Area(ΔPQR) = (AB/PQ)² = (BC/QR)² = (AC/PR)²
Right Triangle Area
Area = ½ × base × height
Heron's Formula
Area = √[s(s-a)(s-b)(s-c)]
where s = (a+b+c)/2
Task 2: Area Calculation
Two similar triangles have corresponding sides in the ratio 3:5. What is the ratio of their areas? If the area of the smaller triangle is 36 cm², what is the area of the larger triangle?
6.6 Geometric Tools and Constructions
Geometric constructions help us understand triangle properties and relationships better.
Compass
Used for drawing arcs and circles, transferring distances
Ruler
Used for drawing straight lines and measuring lengths
Protractor
Used for measuring and constructing angles
Construction: Similar Triangles
Construct a triangle similar to a given triangle with scale factor 3/4. List the steps of your construction and verify that the constructed triangle is indeed similar to the original triangle.
Section B: Multiple Choice Questions
Q1. In two similar triangles, the ratio of their corresponding sides is 4:9. What is the ratio of their areas?
- A. 2:3
- B. 4:9
- C. 16:81
- D. 64:729
Q2. In a right triangle, the hypotenuse is 10 cm and one side is 6 cm. What is the length of the third side?
- A. 4 cm
- B. 6 cm
- C. 8 cm
- D. 12 cm
Q3. Which of the following is not a criterion for similarity of triangles?
- A. AAA
- B. SSS
- C. SAS
- D. SSA
Q4. In an equilateral triangle, each exterior angle measures:
- A. 60°
- B. 90°
- C. 120°
- D. 180°
Q5. The Basic Proportionality Theorem is also known as:
- A. Pythagoras Theorem
- B. Thales Theorem
- C. Euclid's Theorem
- D. Archimedes' Principle
Section C: Answer in Detail (For Answer Writing Practice)
📝 Multiple Choice Questions (MCQs)
-
In a right triangle, the square of the hypotenuse is equal to:
- Sum of the squares of the other two sides
- Difference of the squares of the other two sides
- Product of the other two sides
- None of these
-
If two triangles are similar, then their corresponding angles are:
- Equal
- Proportional
- Right
- Congruent
-
Which of the following is not a criterion for triangle similarity?
- SSS
- SAS
- AAA
- ASA
-
In ΔABC, DE || BC. If AD = 2 cm, DB = 4 cm, then AE : EC =
- 1 : 2
- 2 : 1
- 1 : 3
- 3 : 1
-
The sides of two similar triangles are in the ratio 2:3. What is the ratio of their areas?
- 2 : 3
- 4 : 9
- 3 : 2
- 9 : 4
-
The Pythagoras theorem is applicable only in:
- Equilateral triangle
- Right triangle
- Isosceles triangle
- Scalene triangle
-
In ΔXYZ ~ ΔPQR, XY = 6 cm, YZ = 8 cm, PQ = 9 cm. What is QR?
- 10 cm
- 12 cm
- 15 cm
- 8 cm
-
A triangle whose all sides are equal is called:
- Scalene
- Isosceles
- Equilateral
- Right-angled
-
In ΔABC, if AB = AC, then ΔABC is:
- Scalene
- Equilateral
- Right-angled
- Isosceles
-
Which tool is most commonly used to draw a circle?
- Protractor
- Compass
- Set-square
- Divider
-
The ratio of the areas of two similar triangles is equal to the square of the ratio of their:
- Perimeters
- Altitudes
- Sides
- Angles
-
A triangle with no equal sides is called:
- Scalene
- Isosceles
- Equilateral
- Right-angled
-
The Pythagoras theorem can also be written as:
- a² + b² = c²
- a² - b² = c²
- a² × b² = c²
- a² ÷ b² = c²
-
The square root of the area ratio of two similar triangles gives the ratio of their:
- Sides
- Angles
- Perimeters
- Altitudes
-
Which of the following is not a type of triangle?
- Scalene
- Isosceles
- Equiangular
- Square
-
The altitude drawn to the hypotenuse of a right triangle divides it into:
- Two equal triangles
- Two isosceles triangles
- Two similar triangles
- None of these
-
Which similarity criterion is used when two triangles have one equal angle and the sides including these angles are proportional?
- AAA
- SSS
- SAS
- ASA
-
The line drawn from the vertex of a triangle perpendicular to the opposite side is called:
- Median
- Altitude
- Angle bisector
- Perpendicular bisector
-
The longest side of a right-angled triangle is called:
- Base
- Altitude
- Hypotenuse
- Median
-
In ΔABC, if ∠A = 90°, AB = 3 cm, AC = 4 cm, then BC =
- 5 cm
- 6 cm
- 7 cm
- 12 cm
✅ Answer Key (MCQs)
- a
- a
- d
- c
- b
- b
- b
- c
- d
- b
- c
- a
- a
- a
- d
- c
- c
- b
- c
- a
Q1. State and prove the Basic Proportionality Theorem. Use a diagram to illustrate the theorem.
Hint: Include given, to prove, construction, and proof with proper reasoning.
Q2. Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
Hint: Use the formula for area of triangle and property of similar triangles.
Q3. Explain the converse of Pythagoras Theorem with an example. How is it used to determine if a triangle is right-angled?
Hint: Include statement, explanation, and a numerical example.
Section D: Tackle These! (Higher Order Thinking Skills - HOTS)
Q1. In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9AD² = 7AB².
Think about: Using Pythagoras theorem in right triangles formed by drawing altitude.
Q2. The perpendicular from A on side BC of a ΔABC intersects BC at D such that DB = 3CD. Prove that 2AB² = 2AC² + BC².
Think about: Applying Pythagoras theorem in triangles ABD and ACD.
Q3. In a right triangle, the hypotenuse is 5 cm. If one side is increased by 2 cm and the other side is increased by 3 cm, the hypotenuse becomes 6√2 cm. Find the lengths of the sides of the original triangle.
Think about: Setting up equations using Pythagoras theorem.
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